Physics - Capacitor Question with Solution | TestHub

Here, Frequency, $v=6\times 10^{14}\mathrm{Hz}$ Work-function, $\varphi =2\mathrm{eV}=2\times 1.6\times 10^{-19}\mathrm{J}$ $=3.2\times 10^{-19}\mathrm{J}$ Maximum energy, ${\mathrm{T}}_{\max }=$ ? By Einstein's photo electric equation, we have $\begin{array}{rl}& hv=\varphi +T_{\max }\\ \Rightarrow & T_{\max }=hv-\varphi \\ =& \left(6.63\times 10^{-34}\times 6\times 10^{14}\right)-\left(3.2\times 10^{-19}\right)\\ =& \left(3.97\times 10^{-19}\right)-\left(3.2\times 10^{-19}\right)\\ =& 0.77\times 10^{-19}\mathrm{J}\\ =& \frac{0.77\times 10^{-19}}{1.6\times 10^{-19}}\mathrm{eV}=0.49\mathrm{eV}\end{array}$