In triangle O ( 0 , 0 ) , A ( 2 , 0 ) , B = ( 1 , 1/ 3 ) , let R be the region of interior points P satisfying d ( P , O A ) ≤ min { d ( P , OB ) , d ( P , A B )} . Find the area of the triangle outside R .

Start Free Mock LoginAlready registered? Login here

Mathematics - Straight Lines Question with Solution | TestHub

MathematicsStraight LinesAngle bisectorsMedium2 minQB

MathematicsMediumsingle choice

In triangle $O (0, 0), A (2, 0), B = (1, 1/ 3)$ , let $R$ be the region of interior points $P$ satisfying $d (P, O A) \leq$ $min {d (P, OB), d (P, A B)}$ . Find the area of the triangle outside $R$ .

Options:

Answer:

Solution:

The full triangle area is $1/ 3$ . Subtract $[R] = 2 - 3$ to get $1/ 3 - 2 + 3 = 2 (2 - 3) / 3$ .

Stream:JEESubject:MathematicsTopic:Straight LinesSubtopic:Angle bisectors

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...