Mathematics - Straight Lines Question with Solution | TestHub
MathematicsStraight LinesConcurrency & Family of LinesMedium2 minQB
MathematicsMediummatching list
Match the statements to points.
Column I | Column II |
|---|---|
(A) 2a, b, c in A.P.; concurrency of ax+by=c | (p) (-1, 1) |
(B) Orthocentre: x+y=0, x-y+4=0, x+2y+1=0 | (q) (1, -1) |
(C) Circumcentre of side-midpoint triangle: x-y+8=0, x=0, y=0 | (r) (2, -2) |
(D) Incentre: x=0, y=0, 3x-4y-12=0 | (s) (-2, 2) |
Options:
Answer:
A
Solution:
A: gives and concurrent point . B: the first two sides meet orthogonally at (-2, 2). C: the original triangle has vertices (0, 0), (-8, 0), (0, 8), and the nine-point centre is (-2, 2). D: the 3-4-5 right triangle has inradius 1, giving (1, -1).
Stream:JEESubject:MathematicsTopic:Straight LinesSubtopic:Concurrency & Family of Lines
⏱ 2mℹ️ Source: QB
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