Mathematics - Statistics Question with Solution | TestHub

Median is given as $$M=l+\frac{\frac{N}{2}-F}{f}\times C$$ where $l=$ lower limit of the median - class $f=$ frequency of the median class $N=$ total frequency $F=$ cumulative frequency of the class just before the median class $C=$ length of median class Now, given, $M=25,N=100,F=45$, $C=20-30=10,l=20$. $\therefore$ By using formula, we have $$\begin{array}{rl}& 25=20+\frac{50-45}{f}\times 10\\ & 25-20=\frac{50}{f}\Rightarrow 5=\frac{50}{f}\Rightarrow f=10\end{array}$$