Mathematics - Sequence & Series Question with Solution | TestHub

$6912=2^8{3}^3,52480=2^8\cdot 5\cdot 41$, and $32000=2^8{5}^3$. Their divisor counts are $9\cdot 4=36,9\cdot 2\cdot 2=36$, and $9\cdot 4=36$. The constant nonzero sequence (36, 36, 36) is an A.P., G.P. and H.P.