Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesMiscellaneous/MixedMedium2 minPYQ_2021
MathematicsMediumstatement

Leta,b,cbe in arithmetic progression. Let the centroid of the triangle with verticesa,c,2,banda,bbe103,73.Ifα,βare the roots of the equationax2+bx+1=0,then the value ofα2+β2-αβis:

Options:

Answer:
A
Solution:

a+2+a3=103

a=4

and c+b+b3=73

c+2b=7

also 2b=a+c

2b-a+2b=7

b=114

now 4x2+114x+1=0

 

α2+β2-αβ=α+β2-3αβ

=-11162-314

=121256-34=-71256

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:Miscellaneous/Mixed
2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...