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Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesMeans / inequalityEasy2 minPYQ_2007

MathematicsEasystatement

If $p$ and $q$ are positive real numbers such that $p^{2} + q^{2} = 1$ , then the maximum value of $(p + q)$ is

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Answer:

Solution:

Using $A . M .$ $\geq$ $G . M .$ $\frac{p ^{2} + q ^{2}}{2} \geq pq \Rightarrow pq \leq \frac{1}{2} (p + q)^{2} = p^{2} + q^{2} + 2 pq \Rightarrow p + q \leq 2 .$

Stream:JEESubject:MathematicsTopic:Sequence & SeriesSubtopic:Means / inequality

⏱ 2mℹ️ Source: PYQ_2007

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