Mathematics - Sequence & Series Question with Solution | TestHub

MathematicsSequence & SeriesG.P.Medium2 minPYQ_2021
MathematicsMediumsingle choice

Paragraph: Let , where Consider the geometric progression Let and, for , let denote the sum of the first terms of this progression. For , let denote the circle with center and radius , and denote the circle with center and radius .
Question: Consider with . Let be the number of all those circles that are inside . Let be the maximum possible number of circles among these circles such that no two circles intersect. Then

Options:

Answer:
D
Solution:

Sn=1+12+122++12n-1

=21-12n=2-12n-1

Centre of Cn is 2-12n-2,0

and radius of Cn is 12n-1

when r=1025 513<2

Cn will lie inside m

when 2-12n-2+12n-1<1025 513

1-12n<10251026

2n<1026n10

Hence number of circles

k=10

Also =5

3k+2=30+10=40

Stream:JEE_ADVSubject:MathematicsTopic:Sequence & SeriesSubtopic:G.P.
2mℹ️ Source: PYQ_2021

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