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Mathematics - Quadratic Equation Question with Solution | TestHub

MathematicsQuadratic EquationTheory of equationsMedium2 minPYQ_2021
MathematicsMediumnumerical

Ifα,βare roots of the equationx2+52x+10=0,α>βandPn=αn-βnfor each positive integern,then the value ofP17P20+52P17P19P18P19+52P182is equal to

Answer:
1.00
Solution:

Given, x2+52x+10=0

and  Pn=αn-βn 

Now P17P20+52P17P19P18P19+52P182=P17P20+52P19P18P19+52P18

=P17α20-β20+52α19-β19P18α19-β19+52α18-β18

=P17α19α+52-β19β+52P18α18α+52-β18β+52

Since α+52=-10/α       ...1

& β+52=-10/β       ...2

Now put these values in above expression

P17α19α+52-β19β+52P18α18α+52-β18β+52=-10P17P18-10P18P17=1

Stream:JEESubject:MathematicsTopic:Quadratic EquationSubtopic:Theory of equations
2mℹ️ Source: PYQ_2021

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