Mathematics - Quadratic Equation Question with Solution | TestHub

We have, ${\left|x\right|}^2-\left|x\right|-12=0$

$\Rightarrow {\left|x\right|}^2-4\left|x\right|+3\left|x\right|-12=0$

$\Rightarrow \left(\left|x\right|+3\right)\left(\left|x\right|-4\right)=0$

$\Rightarrow \left|x\right|=4$ as $\left|x\right|\ne -3$

$\Rightarrow x=\pm 2$

Hence, number of real solution is $2.$