The numbers a , b are chosen from the set { 1 , 2 , 3 , 4 , − ⋯ , 10 } such that a ≤ b with replacement. The probability that a divides b is

Number of ways of choosing a & b s.t a ≤ b = 10 + 9 + 8 + − − − + 1 = 55 " a & b s.t a divides b = 10 + 5 + 3 + 2 + 2 + 5 = 27 ∴ Required probability = 55 27

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MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Easy2 minQB

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The numbers $a, b$ are chosen from the set ${1, 2, 3, 4, - \dots, 10}$ such that $a \leq b$ with replacement. The probability that $a$ divides $b$ is

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Solution:

Number of ways of choosing $a & b$ s.t $a \leq b = 10 + 9 + 8 + - - - + 1 = 55$ " $a & b$ s.t $a$ divides $b = 10 + 5 + 3 + 2 + 2 + 5 = 27$ ∴ Required probability $= \frac{27}{55}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

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