Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Easy2 minQB

MathematicsEasyinteger

In a group of people, if 4 are selected at a random, the probability that any two of the four do not have same month of birth is $p$ then $\frac{96 P}{11}$ is equal to

Answer:

Solution:

Required probability $=^{12} C_{4} 44 - 55$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)

⏱ 2mℹ️ Source: QB

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