Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeometrical ProbabilityHard2 minQB

MathematicsHardsingle choice

If $x, y, z \in R$ and $x + y + z = 5, x y + yz + z x = 3$ , probability for x to be positive only is

Answer:

Solution:

Range of x is $⌈ - 1, \frac{13}{\frac{3}{3}} ⌉$ Since probability of x to be

$\int_{- 1}^{\frac{13}{3}} d x = \frac{\frac{13}{3}}{\frac{13}{3} + 1} = \frac{13}{16}$

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Geometrical Probability

⏱ 2mℹ️ Source: QB

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