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Mathematics - Probability Question with Solution | TestHub

MathematicsProbabilityGeneral (Event SS, Definitions, Odd against/Favour)Medium2 minPYQ_2014
MathematicsMediumsingle choice

Paragraph: Box contains three cards bearing numbers ; box contains five cards bearing numbers ; and box contains seven cards bearing numbers . A card is drawn from each of the boxes. Let be the number on the card drawn from the box, .
Question: The probability that is odd, is

Options:

Answer:
B
Solution:

Case I: One odd, 2 even
Total number of ways=2×2×3+1×3×3+1×2×4=29
Case II: All 3 odd
Number of ways=2×3×4=24
Favourable ways = 53
Required probability=533×5×7=53105

Stream:JEE_ADVSubject:MathematicsTopic:ProbabilitySubtopic:General (Event SS, Definitions, Odd against/Favour)
2mℹ️ Source: PYQ_2014

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