If P ( A ) = 3/4 , P ( A ∩ B ˉ ∩ C ) = 1/3 , and P ( A ∩ B ˉ ∩ C ˉ ) = 1/3 , find P ( A ∩ C ) .

The two given disjoint parts show P ( A ∩ C ˉ ) = 2/3 . Therefore P ( A ∩ C ) = 3/4 − 2/3 = 1/12 .

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If $P (A) = 3/4, P (A \cap \overset{ˉ}{B} \cap C) = 1/3$ , and $P (A \cap \overset{ˉ}{B} \cap \overset{ˉ}{C}) = 1/3$ , find $P (A \cap C)$ .

Answer:

Solution:

The two given disjoint parts show $P (A \cap \overset{ˉ}{C}) = 2/3$ . Therefore $P (A \cap C) = 3/4 - 2/3 = 1/12$ .

Stream:JEESubject:MathematicsTopic:ProbabilitySubtopic:Geometrical Probability

⏱ 2mℹ️ Source: QB

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