Mathematics - Probability Question with Solution | TestHub

$\begin{array}{rl}& 2p+2q=\frac{1}{2}\\ & p+q\\ & E\left(x^2\right)=\sum _{i=0}^3{x}_i^{2}p\left(x_i\right)=0\cdot p+1\cdot p+4\cdot q+9q\\ & =p+13q\\ & E(x)=\sum _{i=0}^3{x}_i^{2}p\left(x_i\right)=0\cdot p+1\cdot p+2q+3q=p+5q\\ & p+13q=2(p+5q)\\ & p=3q\\ & \text{ So, }q=\frac{1}{8}\&p=\frac{3}{8}\\ & \text{ So, }8p-1=2\text{ Option (2) }\end{array}$