The vectors AB = 3 i ^ + 4 k ^ & AC = 5 i ^ − 2 j ^ + 4 k ^ are the sides of a triangle ABC . The length of the median through A is

P.V of AD = 2 ( 3 + 5 ) i + ( 0 − 2 ) j + ( 4 + 4 ) k = 4 i − j + 4 k or ∣ AD ∣ = 16 + 16 + 1 = 33

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MathematicsPointLocusMedium2 minPYQ_2003

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The vectors $AB = 3 \hat{i} + 4 \hat{k} & AC = 5 \hat{i} - 2 \hat{j} + 4 \hat{k}$ are the sides of a triangle $ABC$ . The length of the median through $A$ is

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P.V of $AD = \frac{( 3 + 5 ) i + ( 0 - 2 ) j + ( 4 + 4 ) k}{2}$ $= 4 i - j + 4 k$ or $∣ AD ∣ = 16 + 16 + 1 = 33$

Stream:JEESubject:MathematicsTopic:PointSubtopic:Locus

⏱ 2mℹ️ Source: PYQ_2003

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