If the equation of the locus of a point equidistant from the point ( a 1 , b 1 ) and ( a 2 , b 2 ) is ( a 1 − b 2 ) x + ( a 1 − b 2 ) y + c = 0 , then the value of 'c' is

Question

If the equation of the locus of a point equidistant from the point ( a 1 ​ , b 1 ​ ) and ( a 2 ​ , b 2 ​ ) is ( a 1 ​ − b 2 ​ ) x + ( a 1 ​ − b 2 ​ ) y + c = 0 , then the value of 'c' is

TestHub · Accepted Answer

( h − a 1 ​ ) 2 + ( k − b 1 ​ ) 2 = ( h − a 2 ​ ) 2 + ( k − b 2 ​ ) 2 ( a 1 ​ − a 2 ​ ) x + ( b 1 ​ − b 2 ​ ) y + 2 1 ​ ( a 2 2 ​ + b 2 2 ​ − a 1 2 ​ − b 1 2 ​ ) = 0 C = 2 1 ​ ( a 2 2 ​ + b 2 2 ​ − a 1 2 ​ − b 1 2 ​ )

Mathematics - Point Question with Solution | TestHub

Options:

Doubts & Discussion