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Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationnPr & nCrEasy2 minQB

MathematicsEasysingle choice

A student is to answer 10 out of 13 questions in an examination such that he must choose at least 4 from the first five questions. The number of choices available to him is .

Options:

Answer:

Solution:

The number of choices available to him is

$^{5} C_{4} \times^{8} C_{6} +^{5} C_{4} \times^{8} C_{5}$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr

⏱ 2mℹ️ Source: QB

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