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Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationFundamental PrincipleMedium2 minQB

MathematicsMediumsingle choice

There are 3 rows containing 2 seats in each row. The number of ways in which 3 persons can be seated such that no row remains empty is p then $\frac{p}{16} =$

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Answer:

Solution:

$R_{1}, R_{2}, R_{3}$ contain 1 person each $^{2} C_{1} \cdot^{2} C_{1} \cdot^{2} C_{1} 3! = P \frac{8.6}{16} = \frac{48}{16} = 3$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:Fundamental Principle

⏱ 2mℹ️ Source: QB

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