The number of ways in which 4 married couples can be sit four on each side of a long table so that males on one side and females on the other side and no wife is in front of her husband is k then k is $____$
Options:
Answer:
B
Solution:
$K = 4! (\frac{1}{2 !} - \frac{1}{3 !} + \frac{1}{4 !}) = 12 - 4 + 1 = 9$

Question

The number of ways in which 4 married couples can be sit four on each side of a long table so that males on one side and females on the other side and no wife is in front of her husband is k then k is $____$

Options:

Answer:

B

Solution:

$K = 4! (\frac{1}{2 !} - \frac{1}{3 !} + \frac{1}{4 !}) = 12 - 4 + 1 = 9$

TestHub · Accepted Answer

K = 4 ! ( 2 ! 1 ​ − 3 ! 1 ​ + 4 ! 1 ​ ) = 12 − 4 + 1 = 9

Mathematics - Permutation & Combination Question with Solution | TestHub

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