Mathematics - Permutation & Combination Question with Solution | TestHub

MathematicsPermutation & CombinationnPr & nCrMedium2 minPYQ_2024

MathematicsMediumsingle choice

The number of ways five alphabets can be chosen from the alphabets of the word MATHEMATICS, where the chosen alphabets are not necessarily distinct, is equal to :

Options:

Answer:

Solution:

AA, MM, TT, H, I, C, S, E (1) All distinct $^{8} C_{5} \to 56$ (2) 2 same, 3 different $^{3} C_{1} \times^{7} C_{3} \to 105$ (3) 2 same $I^{st}$ kind, 2 same $2^{nd}$ kind, 1 different $^{3} C_{2} \times^{6} C_{1} \to 18$ Total $\to 179$

Stream:JEESubject:MathematicsTopic:Permutation & CombinationSubtopic:nPr & nCr

⏱ 2mℹ️ Source: PYQ_2024

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