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MathematicsPermutation CombinationArrangement under ConstraintHard2 minPYQ_2014
MathematicsHardnumerical

Letn1<n2<n3<n4<n5be positive integers such thatn1+n2+n3+n4+n5=20. Then the number of such distinct arrangementsn1, n2, n3, n4, n5is _________

Answer:
7.00
Solution:

Whenn5takes value from 10 to 6 the carry forward moves from 0 to 4 which can be arranged in4C0+4C14+4C22+4C41=7
Alternate solution
Possible solutions are
1, 2, 3, 4, 10
1, 2, 3, 5, 9
1, 2, 3, 6, 8
1, 2, 4, 5, 8
1, 2, 4, 6, 7
1, 3, 4, 5, 7
2, 3, 4, 5, 6
Hence 7 solutions are there.

Stream:JEE_ADVSubject:MathematicsTopic:Permutation CombinationSubtopic:Arrangement under Constraint
2mℹ️ Source: PYQ_2014

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