Mathematics - Permutation & Combination Question with Solution | TestHub

4 novels can be selected from 6 novels in ${}^6{\mathrm{C}}_4$ ways. 1 dictionary can be selected from 3 dictionaries in ${}^3{\mathrm{C}}_1$ ways. As the dictionary selected is fixed in the middle, the remaining 4 novels can be arranged in 4 ! ways. $\therefore$ The required number of ways of arrangement $={}^6{\mathrm{C}}_4\times {}^3{\mathrm{C}}_1\times 4!=1080$