The shortest distance between parabolas y 2 = x − 1 and x 2 = y − 1 is k 3 2 , then numerical value of k is

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The shortest distance between parabolas $y^{2} = x - 1$ and $x^{2} = y - 1$ is $\frac{3 2}{k}$ , then numerical value of $k$ is

Answer:

Both the curves are symmetrical about the line $y=x$. Distance between any pair of points $= 2\left\{\right.$ distance of $\left(t, t^{2}+1\right)$ from $\left.y=x\right]$

Solution:

Stream:JEESubject:MathematicsTopic:Parabola

⏱ 2m

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