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MathematicsParabolaMiscellaneous/MixedMedium2 minQB

MathematicsMediuminteger

If $e$ is the eccentricity of the hyperbola $(5 x - 10)^{2} + (5 y + 15)^{2} = (12 x - 5 y + 1)^{2}$ then $\frac{25 e}{13}$ is equal to $____$

Answer:

Solution:

Equation can be rewritten as $(x - 2)^{2} + (y + 3)^{2} = \frac{13}{5} \frac{12 x - 5 y + 1}{13}$ So, $e = \frac{13}{5}$ .

Stream:JEESubject:MathematicsTopic:ParabolaSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: QB

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