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Mathematics - Parabola Question with Solution | TestHub

MathematicsParabolaNormal to ParabolaMedium2 minQB

MathematicsMediumsingle choice

The points on the axis of the parabola $3 y^{2} + 4 y - 6 x + 8 = 0$ from where 3 distinct normals can be drawn is given by

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$3 y^{2} + 4 y = 6 x - 8$ $\Rightarrow 3 (y^{2} + \frac{4}{3} y) = 6 x - 8 \Rightarrow (y + \frac{2}{3})^{2} = 2 x - \frac{8}{3} + \frac{4}{9} \Rightarrow (y + \frac{2}{3})^{2} = 2 (x - \frac{10}{9})$

Let any point on the axis $(a, - \frac{2}{3})$

Stream:JEESubject:MathematicsTopic:ParabolaSubtopic:Normal to Parabola

⏱ 2mℹ️ Source: QB

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