Mathematics - Parabola Question with Solution | TestHub

$y+tx=2t+t^3$

$6t=2t+t^3$

$\begin{array}{c}\Rightarrow t^2+2-6=0t=\pm 2\end{array}$

$\therefore A\equiv (4,4)$ $\therefore \text{ Minimum distance }\sqrt{4+16}-\sqrt{5}=\sqrt{20}-\sqrt{5}\text{. }$