Mathematics - Parabola Question with Solution | TestHub

Centre of circle $(a,0)$ and radius $2a$

Equation of circle ${\left(\begin{array}{ll}x& a\end{array}\right)}^2$ | $y^2=4a^2$

$x^2+y^2-2ax-3a^2=0$ and $y^2=4ax$ solving $x^2+4ax-2ax-3x^2=0$ $x^2+2ax-3a^2=0$ $x=-3a,a$ and $y=\pm 2a$

∴ Length of $AB=4a$