OAB is a sector of a circle of radius R in which O , A (where O is the centre of the circle) is fixed and B is a variable point. Then, the locus of centre of a circle inscribed in the sector OAB is eq

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OAB is a sector of a circle of radius R in which O , A (where O is the centre of the circle) is fixed and B is a variable point. Then, the locus of centre of a circle inscribed in the sector OAB is equal to / part of

TestHub · Accepted Answer

Let the radius of the inscribed circle be ' r ' Also h = ( R − r ) cos θ ; k = ( R − r ) sin θ ⇒ h 2 + k 2 = ( R − k ) 2 ⇒ locus is x 2 = − 2 R ( y − 2 R ​ )

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