Start Free Mock LoginAlready registered? Login here

Mathematics - Parabola Question with Solution | TestHub

MathematicsParabolaMiscellaneous/MixedHard3 minQB

MathematicsHardmultiple choice

A point $P$ on $y^{2} = 4 x$ is closest to the centre of $x^{2} + y^{2} - 4 x - 16 y + 64 = 0$ . The segment from $P$ to the centre meets the circle at $Q$ . Which are true?

Options:(select one or more)

Answer:

A, B, C

Solution:

The centre is $(2, 8)$ . A normal $y = - t x + 2 t + t^{3}$ through it gives $t = 2$ , hence $P = (4, 4)$ , distance $25$ , and tangent slope at $Q$ is 1/2.

Stream:JEESubject:MathematicsTopic:ParabolaSubtopic:Miscellaneous/Mixed

⏱ 3mℹ️ Source: QB

Doubts & Discussion

Loading discussions...