Mathematics - Parabola Question with Solution | TestHub
MathematicsParabolaNormal to ParabolaMedium2 minQB
MathematicsMediumsingle choice
The feet of the normals to y² = 4ax from the point (6a, 0) are
Options:
Answer:
D
Solution:
Normal to y²=4ax: y = mx - 2am - am³. Through (6a, 0): 0 = 6am - 2am - am³, so am(m² - 4) = 0, giving m = 0, ±2. Feet = (am², -2am) = (0,0), (4a,-4a), (4a,4a).
Stream:JEESubject:MathematicsTopic:ParabolaSubtopic:Normal to Parabola
⏱ 2mℹ️ Source: QB
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