Mathematics - Parabola Question with Solution | TestHub

We have : $x^2+(8x)=9$ $\Rightarrow x^2+9x-x-9=0$ $\Rightarrow x(x+9)-1(x+9)=0$ $\Rightarrow (x+9)(x-1)=0\Rightarrow x=-9,1$ for $x=1,y=\pm 2\sqrt{2x}=\pm 2\sqrt{2}$ $\sqrt{(2\sqrt{2}+2\sqrt{2}{)}^2+(1-1{)}^2}=4\sqrt{2}$ ${\mathrm{L}}_n=$ Length of latus rectum $=4a=4\times 2=8$ ${\mathrm{L}}_1<{\mathrm{L}}_2$