If the area of the triangle whose one vertex is at the vertex of the parabola, y 2 + 4 ( x − a 2 ) = 0 and the other two vertices are the points of intersection of the parabola and y -axis, is 250 sq.

Question

If the area of the triangle whose one vertex is at the vertex of the parabola, y 2 + 4 ( x − a 2 ) = 0 and the other two vertices are the points of intersection of the parabola and y -axis, is 250 sq. units, then a value of 'a' is :

TestHub · Accepted Answer

y t = − 4 ( x − a 2 ) Area = 2 1 ​ ( 4 a ) ( a 2 ) = 2 a 3 Since 2 a 3 = 250 ⇒ a = 5

Mathematics - Parabola Question with Solution | TestHub

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