Mathematics - Parabola Question with Solution | TestHub

Equations of the sides of the parallelogram are $(x-3)(x-2)=0$ and $(y-5)(y-1)=0$ i.e. $x=3,x=2;y=5,y=1$ Hence its vertices are : $\mathrm{A}(2,1);\mathrm{B}(3,1)$; $\mathrm{C}(3,5);\mathrm{D}(2,5)$ Equation of the diagonal $\mathrm{AC}$ is $y-1=\frac{4}{1}(x-2)\Rightarrow y=4x-7$ Equation of the diagonal $\mathrm{BD}$ is $y-1=\frac{4}{-1}(x-3)\Rightarrow 4x+y=13$