Mathematics - Parabola Question with Solution | TestHub

MathematicsParabolaMiscellaneous/MixedEasy2 minPYQ_2008

MathematicsEasysingle choice

Consider the two curves $C_{1} : y^{2} = 4 x$ $C_{2} : x^{2} + y^{2} - 6 x + 1 = 0$ , then

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Solution:

For the points of intersection of the two given curves $C_{1} : y^{2} = 4 x and C_{2} : x^{2} + y^{2} - 6 x + 1 = 0,$ we have $x^{2} + 4 x - 6 x + 1 = 0 \Rightarrow x^{2} - 2 x + 1 = 0 \Rightarrow (x - 1)^{2} = 0 \Rightarrow x = 1, 1 \Rightarrow y = 2, - 2$ Thus, the given curves touch each other exactly at two points $(1, 2)$ and $(1, - 2)$ .

Stream:JEE_ADVSubject:MathematicsTopic:ParabolaSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2008

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