If lim x → 0 x l o g ( 3 + x ) − l o g ( 3 − x ) = k , the value of k is

Lim x → 0 x l o g ( 3 + x ) − l o g ( 3 − x ) = K (by L'Hospital rule) Lim x → 0 1 3 + x 1 − 3 − x − 1 = K ∴ 3 2 = K

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Mathematics - Limits Question with Solution | TestHub

MathematicsLimitsExponential and logarithmic limitsEasy2 minPYQ_2003

MathematicsEasysingle choice

If $lim_{x \to 0} \frac{l o g ( 3 + x ) - l o g ( 3 - x )}{x} = k$ , the value of $k$ is

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Answer:

Solution:

$Lim_{x \to 0} \frac{l o g ( 3 + x ) - l o g ( 3 - x )}{x} = K$ (by L'Hospital rule) $Lim_{x \to 0} \frac{\frac{1}{3 + x} - \frac{- 1}{3 - x}}{1} = K ∴ \frac{2}{3} = K$

Stream:JEESubject:MathematicsTopic:LimitsSubtopic:Exponential and logarithmic limits

⏱ 2mℹ️ Source: PYQ_2003

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