In the first quadrant, find the area under y=x from x=0 to x= sin − 1 ( a 4 + 1 ) + cos − 1 ( a 4 + 1 ) − tan − 1 ( a 4 + 1 ) , assuming the real inverse functions are defined.

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The real domain forces a⁴+1≤1, so a=0. The right boundary becomes π /2 − π /4 = π /4 . The triangular area is ( π /4 )²/2= π 2 /32 . Note the original options A and D are duplicated, retained here.

Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

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