The number of solutions of the equation sin − 1 ( 2 x 1 + x 2 ) = 2 π sec ( x − 1 ) are

2 x 1 + x 2 ≤ 1 ⇒ ∣ x ∣ = 1 ⇒ x = ± 1 But x = − 1 will not satisfy the equation.

Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsGeneral ( General, Domain, Range & Graph)Easy2 minQB

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The number of solutions of the equation $sin^{- 1} (\frac{1 + x 2}{2 x}) = \frac{π}{2} sec (x - 1)$ are

Answer:

Solution:

$\frac{1 + x ^{2}}{2 x} \leq 1 \Rightarrow ∣ x ∣ = 1 \Rightarrow x = \pm 1$ But $x = - 1$ will not satisfy the equation.

Stream:JEESubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:General ( General, Domain, Range & Graph)

⏱ 2mℹ️ Source: QB

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