The value of sin ( 2 tan − 1 3 1 ) + cos ( tan − 1 2 2 ) is

sin ( tan − 1 4 3 ) + cos ( tan − 1 2 2 ) = sin ( sin − 1 5 3 ) + cos ( cos − 1 3 1 ) = 5 3 + 3 1 = 15 14

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Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsProperties of ITFEasy2 minQB

MathematicsEasysingle choice

The value of $sin (2 tan^{- 1} \frac{1}{3}) + cos (tan^{- 1} 22)$ is

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Answer:

Solution:

$sin (tan^{- 1} \frac{3}{4}) + cos (tan^{- 1} 22) = sin (sin^{- 1} \frac{3}{5}) + cos (cos^{- 1} \frac{1}{3}) = \frac{3}{5} + \frac{1}{3} = \frac{14}{15}$

Stream:JEESubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:Properties of ITF

⏱ 2mℹ️ Source: QB

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