If sin − 1 x + sin − 1 y + sin − 1 z = 2 3 π then ∑ x 201 y 201 ∑ r = 1 2 ( x 100 r + y 103 r ) =

x = y = z = 1 ∴ Required value = 3 4

Mathematics - Inverse Trigonometric Functions Question with Solution | TestHub

MathematicsInverse Trigonometric FunctionsGeneral ( General, Domain, Range & Graph)Easy2 minQB

MathematicsEasysingle choice

If $sin^{- 1} x + sin^{- 1} y + sin^{- 1} z = \frac{3 π}{2}$ then $\frac{\sum _{r = 1}^{2} ( x ^{100 r} + y ^{103 r} )}{\sum x ^{201} y ^{201}} =$

Answer:

Solution:

$x = y = z = 1$

∴ Required value $= \frac{4}{3}$

Stream:JEESubject:MathematicsTopic:Inverse Trigonometric FunctionsSubtopic:General ( General, Domain, Range & Graph)

⏱ 2mℹ️ Source: QB

Loading discussions...