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MathematicsFunctionsFunctional EquationMedium2 minQB
MathematicsMediumnumerical

Letf:RRbe a differentiable function withf0=1and satisfying the equationfx+y=fxf'y+f'xfyfor allx, yR. Then, the value oflogef10is

Answer:
5.00
Solution:

Px,y: fx+y=fxf'y+f'xfy  x, yR
P0,0: f0=f0f'0+f'0f0
1=2f'0
f'0=12
Px,0: fx=fx.f'0+f'x.f0
   fx=12fx+f'x
   f'x=12fx
   fx=e12x
   lnf10=5

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Functional Equation
2mℹ️ Source: QB

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