Start Free Mock LoginAlready registered? Login here

Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsInverseMedium2 minQB

MathematicsMediumsingle choice

Passage / Comprehension

If $f : [0, 2] \to [0, 2]$ is a bijective function defined by $f (x) = ax^{2} + bx + c$ , where

Which of the following is not a value of a?

Options:

Answer:

Solution:

$- \frac{b}{2 a} \leq 0$ or $- \frac{b}{2 a} \geq 2$ $\Rightarrow \frac{2 a + 1}{2 a} \leq 0 or \Rightarrow - \frac{1}{2} \leq a < 0 or 2 a 0 < a \leq \frac{1}{2}$ $∴ a = 1$ is not possible

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Inverse

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...