The range of the function 5 + 4 x 2 + x 4 2 + x 2

f ( x ) = ( x 2 + x ) + ( x 2 + 2 ) 1 1 , x 2 + 2 = t , t ≥ 2 max f ( x ) = 2 + 2 1 1 = 5 2

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MathematicsFunctionsDomain-RangeMedium2 minQB

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The range of the function $\frac{2 + x ^{2}}{5 + 4 x ^{2} + x ^{4}}$

Answer:

Solution:

$f (x) = \frac{1}{( x ^{2} + x ) + \frac{1}{( x ^{2} + 2 )}}, x^{2} + 2 = t, t \geq 2$ $max f (x) = \frac{1}{2 + \frac{1}{2}} = \frac{2}{5}$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Domain-Range

⏱ 2mℹ️ Source: QB

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