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Mathematics - Functions Question with Solution | TestHub

MathematicsFunctionsFunctional EquationHard2 minQB

MathematicsHardsingle choice

Let $f (x)$ be a polynomial one-one function such that

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Answer:

Solution:

Put $x = y = 1 \Rightarrow f (1) = 2$ again put $y = \frac{1}{x} \Rightarrow f (x) + f (\frac{1}{x}) = f (x) f (\frac{1}{x})$ $\Rightarrow f (x) = x^{3} + 1 \Rightarrow g (x) = 0 \forall x \in R - {0} .$

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Functional Equation

⏱ 2mℹ️ Source: QB

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