Mathematics - Functions Question with Solution | TestHub

We have, $y=\left[x^2\right]-[x{]}^2,x\in [0,2]$ i.e., $y=\left[x^2\right],0\le x<1$ $\begin{array}{rlrlrlrlrl}y& =\left[x^2\right]-1,& & 1\le x<2& =\left[x^2\right]-1,& & x=2& =0& & x=2\end{array}$ i.e., $\mathrm{y}=0,0\le x<1$