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MathematicsFunctionsEven-oddMedium2 minPYQ_2019
MathematicsMediumsingle choice

Letfx=ax (a>0)be written asfx=f1x+f2x, wheref1(x)is an even function andf2(x)is an odd function. Thenf1x+y+f1(x-y)equals:

Options:

Answer:
A
Solution:

fx=ax,a>0

fx=ax+a-x+ax-a-x2
f1x=ax+a-x2
f2x=ax-a-x2

f1x+y+f1x-y

=ax+y+a-x-y2+ax-y+a-x+y2
=ax+a-x2ay+a-y

=f1x×2f1y

=2f1xf1y

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Even-odd
2mℹ️ Source: PYQ_2019

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