If [ sin x ] + [ 2 π x ] + [ 5 π 2 x ] = 10 π 9 x when the number of solutions in the interval (30, 40) is (where [.] is GIF)

[ sin x ] = 2 π x − [ 2 π x ] + 5 π 2 x − [ 5 π 2 x ] No. of solutions = 1 .

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MathematicsFunctionsNumber of Solutions (graph)Medium2 minQB

MathematicsMediuminteger

If $[sin x] + [\frac{x}{2 π}] + [\frac{2 x}{5 π}] = \frac{9 x}{10 π}$ when the number of solutions in the interval

(30, 40) is (where [.] is GIF)

Answer:

Solution:

$[sin x] = \frac{x}{2 π} - [\frac{x}{2 π}] + \frac{2 x}{5 π} - [\frac{2 x}{5 π}]$

No. of solutions $= 1$ .

Stream:JEESubject:MathematicsTopic:FunctionsSubtopic:Number of Solutions (graph)

⏱ 2mℹ️ Source: QB

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