Given 2 x − y + 2 z = 2 , x − 2 y + z = − 4 , x + y + λ z = 4 , then the value of λ such that the given system of equation has no solution is

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Since, the system has no solution. ​ 2 1 1 ​ − 1 − 2 1 ​ 2 − 1 λ ​ ​ = 0 ⇒ 2 ( − 2 λ + 1 ) + 1 ( λ + 1 ) + 2 ( 3 ) = 0 ⇒ − 4 λ + 2 + λ + 1 + 6 = 0 ⇒ 3 λ = 9 ⇒ λ = 3

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