Mathematics - Binomial Theorem Question with Solution | TestHub

MathematicsBinomial TheoremProperties of Binomial coefficientsMedium2 minPYQ_2020

MathematicsMediumsingle choice

If a, b, c are three natural numbers in AP and a + $b + c = 21$ then the possible number of values of the ordered triplet $(a, b, c)$ is

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Answer:

Solution:

Let $a = b - d$ and $c = b + d$ , then $a + b + c = 21$ $\Rightarrow b = 7$ So, the equation is $a + c = 14$ $∴$ No. of solution $=$ coeff. of $x^{14}$ in $(x + x^{2} + \dots .)$ $=^{13} C_{12} = 13$

Subject:MathematicsTopic:Binomial TheoremSubtopic:Properties of Binomial coefficients

⏱ 2mℹ️ Source: PYQ_2020

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